Notifications
Clear all

1) Limits

6 Posts
4 Users
1 Likes
61 Views
vrazacademy
(@vrazacademy)
New Member Admin
Joined: 8 months ago
Posts: 2
Topic starter  

limits

Attachment removed

   
Quote
Topic Tags
Shubham Choudhary
(@shubham-choudhary)
New Member
Joined: 8 months ago
Posts: 1
 

Given function must form Indeterminant form for finding value of C 
= [x^5c (1+ 7/x + 2/x^5 )^c - x]

       … (Take x^5 common from first bracket)

=x[x^5c-1 ( 1+ 7/x + 2/x^5)^c - 1]

… (Take X common from both brackets)

    7/x and 2/x^5 can be neglected because as limits tends to infinity. 
for indeterminant for (0.infinity) 

    5C-1 = 0 

    C=1/5

Spoiler
Calculation for C ( Function must be form indeterminant Form )


   
vrazacademy reacted
ReplyQuote
Artrell
(@artrell)
New Member
Joined: 5 months ago
Posts: 2
 

west


   
ReplyQuote
Artrell
(@artrell)
New Member
Joined: 5 months ago
Posts: 2
 

good


   
ReplyQuote
wqaz
 wqaz
(@wqaz)
New Member
Joined: 3 months ago
Posts: 0
 

ok


   
ReplyQuote
wqaz
 wqaz
(@wqaz)
New Member
Joined: 3 months ago
Posts: 0
 

HI Forum contains unread posts


   
ReplyQuote
Share: